AJAX 自学练习 请求与显示

如下:
request.jsp
复制代码 代码如下:
<%@ page language="Java" contentType="text/html; charset=ISO-8859-1"
pageEncoding="ISO-8859-1"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>Insert title here</title>
<script language="Javascript"><!--
function GetXmlHttpObject(){
    var xmlHttp = null;
    try{
        xmlHttp = new XMLHttpRequest();
    }catch(e){
        try{
            xmlHttp = new ActiveXObject("Msxml2.XMLHTTP");
        }catch(e){
            xmlHttp = new ActiveXObject("Microsoft.XMLHTTP");
        }
    }
    return xmlHttp;

}
function showMsg(str){
    xmlHttp = GetXmlHttpObject();
    if(xmlHttp == null){
        alert ("you browser don't support the ajax");
         return;

    }
    var url = "response.jsp";
    url = url + "?q="+ str;
    url = url + "&sid ="+ Math.random();
    xmlHttp.onreadystatechange = stateChanged;
    xmlHttp.open("GET", url, true);
    xmlHttp.send(null);
}
function stateChanged()
{
    if(xmlHttp.readyState==4)
    {
        document.getElementById("city").value = xmlHttp.responseText;
    }
}
// --></script>
</head>
<body>
<form name="form1" action="" method="post">
    <label >City Code:</label>
    <input type="text" name="code" onblur = "showMsg(this.value)" />
    <br></br>
    <label>City Name:</label>
    <input type="text" name="city" id="city" ></input>
</form>
</body>
</html>

response.jsp
复制代码 代码如下:
<%@ page language="Java" contentType="text/plain; charset=UTF-8"
pageEncoding="UTF-8"%>
<%@ page import="com.lwf.eus.util.*,Java.util.*,com.lwf.eus.entity.*,com.lwf.eus.bean.*" %>
<%
String code = request.getParameter("q");
System.out.println(code);
if(code.equals("140"))
    out.print("上海");
else if(code.equals("150"))
    out.print("北京");
else if(code.equals("160"))
    out.print("天津");
else
    out.print("未知地");
%>

这里要注意的是由于返回的结果要在文本框中显示,因此在response.jsp中没有<html>等标签,因为测试发现如果有这些标签的话,在cityname文本框中这些标签也会显示。

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